LaddiusMaximus
  • LaddiusMaximus
lim x-->8 (x-8/x^2-64)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Rogue
  • Rogue
Can you factor the denominator into anything? Hint: difference of squares
LaddiusMaximus
  • LaddiusMaximus
?
Rogue
  • Rogue
\[\lim_{x \rightarrow 8} \frac {x-8}{x^2 - 64} = \lim_{x \rightarrow 8} \frac {x-8}{(x-8)(x+8)}\]

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LaddiusMaximus
  • LaddiusMaximus
oh yeah
Rogue
  • Rogue
Your answer should be 1/16. Did you get it?
LaddiusMaximus
  • LaddiusMaximus
no
LaddiusMaximus
  • LaddiusMaximus
I know the (x-8) cancels which leaves 1/ x+8
Rogue
  • Rogue
\[\lim_{x \rightarrow 8} \frac {1}{(x+8)} = \frac {1}{16}\]
Rogue
  • Rogue
Yeah, so just plug in 8.
Rogue
  • Rogue
That's what x approaches in the limit.
LaddiusMaximus
  • LaddiusMaximus
got it! thank you!
Rogue
  • Rogue
Alrighty, no problem :)

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