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anonymous

  • 4 years ago

I need to simplify this problem with radicals.

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  1. anonymous
    • 4 years ago
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    \[6x^6/\sqrt[3]{9^4}\]

  2. precal
    • 4 years ago
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    \[6x^6/\sqrt[3]{9*9*9*9}\] \[6x^6/9\sqrt[3]{9}\] \[2x^6/3\sqrt[3]{9}\]

  3. anonymous
    • 4 years ago
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    My professor had gave me an answer of \[2x^4\sqrt[3]{3^2}\]. I am trying to understand how he came to this conclusion if you can explain it for me.

  4. precal
    • 4 years ago
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    are you sure it is division?

  5. precal
    • 4 years ago
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    \[\sqrt[3]{9}\] is the same as \[\sqrt[3]{3^2}\]

  6. anonymous
    • 4 years ago
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    Yup, it is as I have given it to you.

  7. precal
    • 4 years ago
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    Are you sure you copied it correctly? You would be surprised how common that occurs.

  8. anonymous
    • 4 years ago
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    Bah, you're right. \[6x^6/\sqrt[3]{9x^4}\] I had missed a variable.

  9. anonymous
    • 4 years ago
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    Sorry about that, he is one of the teachers that writes out his homework on a sheet a paper and makes copies of it.

  10. precal
    • 4 years ago
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    ok let me do it again

  11. precal
    • 4 years ago
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    \[6x^6/\left( \sqrt[3]{9x^4}\right)\] \[6x^6/\left( \sqrt[3]{9x*x*x*x}\right)\] \[6x^6/\left( x\sqrt[3]{9x}\right)\] \[6x^5/\left( \sqrt[3]{9x}\right)\]

  12. precal
    • 4 years ago
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    Are you sure you wrote it correctly? We are using laws of exponents. The rules are pretty clear.

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spraguer (Moderator)
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