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anonymous

  • 4 years ago

im stuck in this problem..please help

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  1. anonymous
    • 4 years ago
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    |dw:1327972990128:dw| find the range of values for z

  2. anonymous
    • 4 years ago
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    can u please redraw the figure??

  3. anonymous
    • 4 years ago
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    ok

  4. anonymous
    • 4 years ago
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    |dw:1327973646692:dw| there?..please help?

  5. anonymous
    • 4 years ago
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    that 4z-12 is an angle?

  6. anonymous
    • 4 years ago
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    that's how it's drawn in my book..more like this..|dw:1327974111848:dw|

  7. anonymous
    • 4 years ago
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    but it's same thing right?

  8. anonymous
    • 4 years ago
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    well monster, can u tell if these triangles are right angle?

  9. anonymous
    • 4 years ago
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    none of them are?

  10. anonymous
    • 4 years ago
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    that's really funny, are you sure u have put every information?

  11. anonymous
    • 4 years ago
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    i forgot the 16 on the first triangle..

  12. anonymous
    • 4 years ago
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    |dw:1327974424468:dw|

  13. anonymous
    • 4 years ago
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    so sorry, but i have no idea right now, hope that any other member can help, i'd like to see the solution

  14. anonymous
    • 4 years ago
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    any ideas??

  15. mathmate
    • 4 years ago
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    I see three unknowns, z, a (the shorter length) and b (the longer length). I find only two equations, namely by the cosine rule of each triangle. Also, z appears in only one place, so that's "fishy". Can you dig out some more information from the question? For example, copy the question verbatim?

  16. anonymous
    • 4 years ago
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    Omar- Thank's Anyways Math Mate- i don't know that's all it says on my book..

  17. ash2326
    • 4 years ago
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    65 degrees is opposite to side with length 16 54 degrees is opposite to side with length 4z-19 we know that side opposite to larger angle is larger than the side opposite to smaller angle, so 65>54 16>4z-19 25>4z 25/4>z or z<25/4

  18. mathmate
    • 4 years ago
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    Good job! I didn't even read the question line. Grrr.

  19. anonymous
    • 4 years ago
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    That just clicked..thank you ash2326 (:

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