## anonymous 4 years ago Suppose f(x)=A+x for x < 2 and f(x) =5 + x^2 for x greater/equal to 2. Find a value of A such that the function f(x) is continuous at the point x=2. A=

1. anonymous

pizza: its the same prob i posted earlier

2. anonymous

f(x) =5 + x^2 f(2)=9 so 9=A+2 A=7

3. Akshay_Budhkar

$x \rightarrow -2, x \rightarrow 2$ must give the same value of f

4. Akshay_Budhkar

so u have what pizza did above ^

5. anonymous

basically f(2)=lim x->(2+) f(2)=lim x->(2-) f(2)

6. Akshay_Budhkar

btw it is a typo i meant$x \rightarrow 2 ^-$ not$x \rightarrow-2$ :P

7. anonymous

ok i think i got it lol