anonymous
  • anonymous
Find the limit as t tends to ZERO from the RIGHT. lim 21sqrt(t) / t t->0+
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
21 is NOT the answer
myininaya
  • myininaya
\[\lim_{t \rightarrow 0^+}\frac{21 \sqrt{t}}{t} \cdot \frac{\sqrt{t}}{\sqrt{t}}=\lim_{t \rightarrow 0^+}\frac{21(t)}{t \sqrt{t}}=\lim_{t \rightarrow 0^+}\frac{21}{\sqrt{t}}\] Does not exist To be more exact if approaches positive infinity
myininaya
  • myininaya
it*

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anonymous
  • anonymous
so any time i see a square root with a zero inside, the answer will be infinity or DNE?
anonymous
  • anonymous
\[\sqrt{t}\] is in the denominator, so as numbers get closer and closer to 0, the limit approaches infinity

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