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anonymous
 4 years ago
Find the limit as t tends to ZERO from the RIGHT.
lim 21sqrt(t) / t
t>0+
anonymous
 4 years ago
Find the limit as t tends to ZERO from the RIGHT. lim 21sqrt(t) / t t>0+

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{t \rightarrow 0^+}\frac{21 \sqrt{t}}{t} \cdot \frac{\sqrt{t}}{\sqrt{t}}=\lim_{t \rightarrow 0^+}\frac{21(t)}{t \sqrt{t}}=\lim_{t \rightarrow 0^+}\frac{21}{\sqrt{t}}\] Does not exist To be more exact if approaches positive infinity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so any time i see a square root with a zero inside, the answer will be infinity or DNE?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{t}\] is in the denominator, so as numbers get closer and closer to 0, the limit approaches infinity
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