## anonymous 4 years ago few question about e

1. anonymous

1/(e^kt) = e^-kt ?, where as k is a constant

2. anonymous

this is the laws of exponents. $b^{-n}=\frac{1}{b^n}$

3. anonymous

so, e^(kt)t=e^(kt)A+C, solving for t, u get t=e^(-kt)A+e^(-kt)C ?

4. anonymous

e^(kt)T=e^(kt)A+C, solve for big T,

5. anonymous

hold the phone. what are you solving here? it is always the case that $\frac{1}{e^{kt}}=e^{-kt}$

6. anonymous

got cha, thanks