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anonymous
 4 years ago
What is the freezing point of an aqueous solution that boils at 103.7 degrees celsius?
anonymous
 4 years ago
What is the freezing point of an aqueous solution that boils at 103.7 degrees celsius?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In this case, you need to take your equations for boiling point elevation and freezing point depression and combine them...\[\Delta T_b=K_b*m*i\]\[\Delta T_f=K_f*m*i\]Solve for (m * i) in the first equation, and then substitute that into the second to get...\[\Delta T_f=K_f*\frac{\Delta T_b}{K_b}\]K_f for water is 1.86 K/m, and K_b for water is 0.512K/m. \[\Delta T_f=(1.86 K*C^{1})*\frac{103.7C100C}{0.512K*C^{1}}\]If we solve for deltaT_f, we get 13.4C, and since the normal freezing point for water is 0C, the depressed freezing point is...\[13.4 C\]
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