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anonymous
 4 years ago
find the antiderivative
anonymous
 4 years ago
find the antiderivative

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{?}2x/(x1)^{2}\] the ? doesn't mean anything

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0try \[u=x1\] \[du=dx\] and \[x=u1\] so \[2x = 2u2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops sorry if \[u=x1\] then \[x=u+1\] and \[2x=2u+2\] my mistake

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes but after that the (2x+2) *u^2 would equal 2u^1 +2u^2 and ln is required for the 1 exponent and that is what i am having trouble with

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you should have only "u" involved. as follows \[\int\frac{2u+2}{u^2}du\] then break it in to two parts

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int \frac{2u}{u^2}du+\int \frac{2}{u^2}du\] first one becomes \[\int \frac{2}{u}du\] whose "anti derivative" is the log

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oooh i see what you are asking. you cannot use the power rule backwards when integrating \[\int \frac{1}{x}dx\] that is \[\frac{1}{x}dx=\ln(x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhhhh ok i understand that now thanks

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i meant of course \[\int \frac{1}{x}dx=\ln(x)\]
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