so can i get help on this one??..

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so can i get help on this one??..

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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question?
|dw:1327976455407:dw| find the range value for z????
I've been blankly staring this. Is this even possible??

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i don't know..that's why i got no clue.. -_-
z+11>4z-6 17>3z 17/3>z ???
What level math is this?
10th Geometry
Any other info at all about the picture?
|dw:1327977277534:dw| that they are congruent..
i'm sorry but i don't understand this at all.. D:
No..wait..i was looking at it from the wrong angle..myy badd
z>17/3
Thanks's
The two triangles have two congruent sides. The third side (z+11) which is opposite the 122 degree angle must be bigger than the side opposite the 90 degree angle. So write z+11> 4z-6 17> 3z 17/3>z or z< 17/3 Cinar is incorrect.
ok thanks

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