14 GRAMS of an electrolyte was dissolved in 41 grams of water, the resulting solution was found to have a molarity of 0.397 mol / L. The freezing point of the solution was determined to be -9.18°C. The freezing point depression constant for water is -1.86°C and pure water may be assumed to freeze at 0°C. If the molecular weight of the electrolyte is 130.3 g/mol and it takes 45 minutes to perform the experiment, what is the freezing point of the solution ? (°C) Can someone explain how to do this?

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\[M = \frac {n}{V}\]

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