## anonymous 4 years ago i need help solving for x

1. anonymous

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2. anonymous

kolbis, its the same process i showed u; try it =)

3. anonymous

or u can use the ration one

4. anonymous

but i cant type in tan(x) in my calculator

5. anonymous

hey satellite, mind telling me how u got the 1,sq3,2 ? for previous triangles?

6. anonymous

nono, this time use tan^-1(x)

7. anonymous

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8. anonymous

there is an equilateral triangle. each angle must be 60 degrees. then if you cut it in half it is pretty clear that the short side is half of the hypotenuse, and pythagoras give the other (long) side

9. anonymous

(i help) i dont even know how i would type that i have a texas instument ti-84 plus wha6t would i type

10. anonymous

u see the tan key? look behind it- it will say tan^-1,,, u gota press 2nd key (blue color i think) then press the tan key

11. anonymous

if you are looking for $\tan^{-1}(\frac{19}{11})$ you would probably hit "shift" or "second" then "tan" which should give you the inverse tangent

12. anonymous

thanks, that made sense with the ratios

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