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  1. mathmate
    • 4 years ago
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    |dw:1327977940554:dw| For each of the two triangles, the angle (96 and 84 deg.) are known, as well as the adjacents sides. You can use cosine rule, c^2=a^2+b^2-2ab cos(C) to find the length of the guy-wires.

  2. mathmate
    • 4 years ago
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    Sorry, a and b in the cosine rule refer to the length of adjacent sides of each angle, not the guy-wires.

  3. Lukecrayonz
    • 4 years ago
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    So just the same problem basically for both sides, just different angles?

  4. Mertsj
    • 4 years ago
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    a^2=75^2+100^2-2(75)(100)cos 96

  5. Mertsj
    • 4 years ago
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    b62=75^2+100^2-2(75)(100)cos84

  6. mathmate
    • 4 years ago
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    Yep, Mertsj got it all sorted out for you!

  7. Mertsj
    • 4 years ago
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    a=131.12

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