A student drives by a stationary police car at 41.7m/s, exactly 7s later the policeman starts after the speeding car, accelerating at a steady 3.75m/s2. How long after the police car begins moving does it take to catch up with the speeding car.
i got 34.8s but its wrong, can anyone explain it.
Xcar= 291.9+41.7t
Xpolice= 1.875t2
Xcar=X police 1.875t2-41.7t-291.2
t=34.8s

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equation i used was Xf= Xi +Vit+ (1/2)at^2

Is 291.9 the distance the car travels in seven seconds?

yea

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