anonymous
  • anonymous
A student drives by a stationary police car at 41.7m/s, exactly 7s later the policeman starts after the speeding car, accelerating at a steady 3.75m/s2. How long after the police car begins moving does it take to catch up with the speeding car. i got 34.8s but its wrong, can anyone explain it. Xcar= 291.9+41.7t Xpolice= 1.875t2 Xcar=X police 1.875t2-41.7t-291.2 t=34.8s
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
equation i used was Xf= Xi +Vit+ (1/2)at^2
anonymous
  • anonymous
Is 291.9 the distance the car travels in seven seconds?
anonymous
  • anonymous
yea

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More answers

anonymous
  • anonymous
Looks good. Double check that you used the correct solution to the quadratic.
anonymous
  • anonymous
Maybe its just a typo in the solution manual......it has 23.8s
anonymous
  • anonymous
The math gods seem to agree. http://www.wolframalpha.com/input/?i=0.5*3.75*%28t-7%29%5E2+%3D+41.7*t
mathmate
  • mathmate
I get 27.833 s.
anonymous
  • anonymous
@mathmate did you use the same equation?
mathmate
  • mathmate
I used your equation (corrected) and got 27.833, which is the same answer as eashmore's answer by subtracting 7 seconds.
mathmate
  • mathmate
Can you double check the data (speed, acceleration, 7 seconds, etc.)
mathmate
  • mathmate
Note that the clock starts when the police car moves, which is t=7 in eashmore's equation.
anonymous
  • anonymous
yea data is correct.......since the police car moves 7 seconds later i have cars position as t+7
anonymous
  • anonymous
Here is a better representation : http://www.wolframalpha.com/input/?i=0.5*3.75*%28t%29%5E2+%3D+41.7*%28t%2B7%29
anonymous
  • anonymous
ok, thanks a lot
mathmate
  • mathmate
Guess the answer key has a typo!

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