anonymous
  • anonymous
D is the midpoint of AC, BDC=BDA prove ABD=CBD
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ash2326
  • ash2326
|dw:1327981805839:dw|
ash2326
  • ash2326
In triangle ABD and CDB AD=DC (Since D is the midpoint) BD= BD (common side) and angle BDA= angle BDC so by SAS (side angle side) the two triangles are congruent using CPCTC angle ABD= angle CBD
anonymous
  • anonymous
By inspection, line AC has to be normal to line BD in order for the angles in question to be equal.\[\text{ABD}=\text{ArcTan }\left[\frac{\text{AD}}{\text{BD}}\right],\text{DBC}=\text{ArcTan }\left[\frac{\text{DC}}{\text{BD}}\right] \]AD=DC, so the angles ABD and DBC are equal to each other.

Looking for something else?

Not the answer you are looking for? Search for more explanations.