## anonymous 4 years ago How would you solve 3onthesqrt(4x-4) +2 =0

1. anonymous

$\sqrt[3]{4x-4} +2 = 0$

2. anonymous

$\sqrt[3]{4x-4} +2 = 0$ $\sqrt[3]{4x-4} =-2$ $(\sqrt[3]{4x-4})^3 =(-2)^3$ $4x-4=-8$ $4x=-4$ $x=-1$

3. anonymous

Thanks, but it wants to know how many solutions there would be as well, so would it be one or?

4. anonymous

only one solution

5. anonymous

thank you so much precalc homework.. it's about to be a long semester

6. anonymous

yw

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