anonymous 4 years ago Are x = √6 and x=-√6 solutions to x²-3x+1 = 0? Explain your answer

1. anonymous

Using the quadratic formula $x=[-b \pm \sqrt{b ^{2}-4ac} ]/2a$ where a = 1; b= -3 and c = 1 we get two answers; x=$3/2 \pm \sqrt{5}/2$, so no

2. anonymous

if $\sqrt{6} , -\sqrt{6}$ are roots then its equation is $(x-\sqrt{6})(x+\sqrt{6})=0$ $x^2-6=0$