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anonymous
 4 years ago
A boy bats a baseball with a certain initial velocity at an angle of 27.0o above the horizontal. In 1.60 s, the ball reaches its highest point in the trajectory. What is the initial velocity of the ball?
anonymous
 4 years ago
A boy bats a baseball with a certain initial velocity at an angle of 27.0o above the horizontal. In 1.60 s, the ball reaches its highest point in the trajectory. What is the initial velocity of the ball?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no much information for me to solve this...is really6 crazy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this a projectile problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just treat the x positions, velocities, and accelerations as separate from the y positions, velocities, and accelerations, and you can use the standard 2D equations for constant acceleration.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i did vf= vigt where vf=0 then i got 15.68 as my answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would i realte that to the angle given

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328027338347:dwdw:1328027461242:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328338055066:dwwe know tht the time period is = 2 sin(theta) / g ... we are also give tht at max height t= 1.6s .. this means tht the time period is halved...!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0krypton... the 15.696 m/s is the vertical component of a right angle velocity triangle where the angle opposite to the 15.696 is 27 degrees... you have to find the hypotenuse using the definition for Sine. I believe you get something in the order of 34.57 m/s.
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