anonymous
  • anonymous
A boy bats a baseball with a certain initial velocity at an angle of 27.0o above the horizontal. In 1.60 s, the ball reaches its highest point in the trajectory. What is the initial velocity of the ball?
MIT 8.01 Physics I Classical Mechanics, Fall 1999
katieb
  • katieb
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anonymous
  • anonymous
no much information for me to solve this...is really6 crazy
anonymous
  • anonymous
this a projectile problem
anonymous
  • anonymous
any idea?

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Xishem
  • Xishem
Just treat the x positions, velocities, and accelerations as separate from the y positions, velocities, and accelerations, and you can use the standard 2D equations for constant acceleration.
Xishem
  • Xishem
*1D
anonymous
  • anonymous
i did vf= vi-gt where vf=0 then i got 15.68 as my answer
anonymous
  • anonymous
how would i realte that to the angle given
anonymous
  • anonymous
|dw:1328027338347:dw||dw:1328027461242:dw|
anonymous
  • anonymous
|dw:1328338055066:dw|we know tht the time period is = 2 sin(theta) / g ... we are also give tht at max height t= 1.6s .. this means tht the time period is halved...!!
anonymous
  • anonymous
krypton... the 15.696 m/s is the vertical component of a right angle velocity triangle where the angle opposite to the 15.696 is 27 degrees... you have to find the hypotenuse using the definition for Sine. I believe you get something in the order of 34.57 m/s.

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