## Lukecrayonz 4 years ago Drawing problem, lost on what to do.

1. Lukecrayonz

|dw:1327989668302:dw|

2. Lukecrayonz

|dw:1327989777153:dw|

3. Directrix

What is the question that goes with this diagram?

4. Lukecrayonz

Just solve for x, c, and d.

5. Directrix

Is the quadrilateral a parallelogram? Check the instructions.

6. Lukecrayonz
7. Lukecrayonz

So yes :P

8. anonymous

a bunch of sine and cosine laws would work

9. anonymous

not sure if there's a faster approach though

10. Lukecrayonz

The section is law of cosines; im going to assume you only use that.

11. anonymous

you could solve for the angle between 35 and d

12. Lukecrayonz

how?;o

13. anonymous

c^2=a^2+b^2-2abcosC

14. anonymous

a=35, b=52, c=25 , solve for C

15. Directrix

Angle theta is 60 because consecutive angles of a parallelogram are supplementary.

16. anonymous

nvm

17. Lukecrayonz
18. anonymous

|dw:1327990671262:dw|

19. Lukecrayonz

Oh wow, the x was right infront of us the whole time!

20. anonymous

|dw:1327990778975:dw|

21. anonymous

solve for alpha and you should be about to get the rest

22. sasogeek

c and d are the full lengths of the diagonals... right?

23. anonymous

no its only half

24. Lukecrayonz

wouldnt it just be 26?

25. anonymous

your angle is wrong though, the 120 should be a 60

26. anonymous

ignore the drawings, have no idea what i was thinking

27. anonymous

but i got it now

28. anonymous

(2d)^2=25^2+35^2-2(25)(35)cos60 (2c)^2=25^2+35^2-2(25)(35)cos120