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anonymous

  • 4 years ago

Integral of (1/(1+y^2)^(3/2))dy???

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  1. anonymous
    • 4 years ago
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    Well do u wanna use u subsitution?

  2. anonymous
    • 4 years ago
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    I don't really know. I tried to integrate by parts, but apparently it's wrong.. or I did it wrong.

  3. anonymous
    • 4 years ago
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    well wrong according to what?

  4. anonymous
    • 4 years ago
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    according to wolframalpha lol

  5. anonymous
    • 4 years ago
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    u can get diff answers depending on the way u integrate but it is in reality all the sam answer

  6. anonymous
    • 4 years ago
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    I think subsitution is easier

  7. anonymous
    • 4 years ago
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    ohhh maybe not

  8. anonymous
    • 4 years ago
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    Well, they put y=tanu and then they did something, but I don't understand it :/

  9. anonymous
    • 4 years ago
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    ohh they used trig subsitution

  10. anonymous
    • 4 years ago
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    but i guess u didnt learn that

  11. anonymous
    • 4 years ago
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    ya that wld be the simplest

  12. anonymous
    • 4 years ago
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    did u learn trig subsitution yet?

  13. anonymous
    • 4 years ago
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    Nope, never learned it. this is for my DE class :(

  14. anonymous
    • 4 years ago
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    lol that is weird

  15. anonymous
    • 4 years ago
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    k give me a sec to figure it out

  16. anonymous
    • 4 years ago
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    ok thanks

  17. razor99
    • 4 years ago
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    |dw:1327991590145:dw|

  18. razor99
    • 4 years ago
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    59% correct iguess

  19. anonymous
    • 4 years ago
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    lol that is wrong

  20. razor99
    • 4 years ago
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    why

  21. anonymous
    • 4 years ago
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    I am getting an ugly one

  22. anonymous
    • 4 years ago
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    oh sal can u help?

  23. anonymous
    • 4 years ago
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    you have to use trig substitution... take a look at this.

  24. anonymous
    • 4 years ago
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    ya but he never learnt that yet

  25. anonymous
    • 4 years ago
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    is this for hmw? or you are just doing problems for fun?

  26. anonymous
    • 4 years ago
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    yah, i read that.. but how does sec^3(tan^-1) = cos??

  27. anonymous
    • 4 years ago
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    i have an exam tomoroww lol

  28. anonymous
    • 4 years ago
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    ok I will show u what i got. u = 1+y^2 du=2ydy (1/2)du=ydy

  29. anonymous
    • 4 years ago
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    y=sqrt(u-1)

  30. anonymous
    • 4 years ago
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    so (1/2) integral (u)^-(2/3)(u-1)^(1/2)du

  31. anonymous
    • 4 years ago
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    sorry i just dont know how to use latex

  32. anonymous
    • 4 years ago
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    rld did you get a solution in the end using ur way?

  33. anonymous
    • 4 years ago
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    ya but an ugly one

  34. anonymous
    • 4 years ago
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    well look at the solution you know how y=tanu , the solution says that at the begining? you substitute y= tanu, then u=tan-1y

  35. anonymous
    • 4 years ago
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    ya sal's method will give u a nice answer and it is the simplest

  36. anonymous
    • 4 years ago
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    and \[\sin^2u+\cos^2u=1\] divide all by \[\cos^2u\] you will get, \[\tan^2u+1=\sec^2u\] you gotta know these identities

  37. anonymous
    • 4 years ago
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    lol the guy disappeared

  38. anonymous
    • 4 years ago
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    lol

  39. anonymous
    • 4 years ago
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    U scared him off

  40. anonymous
    • 4 years ago
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    amma disappear too...

  41. anonymous
    • 4 years ago
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    lol

  42. anonymous
    • 4 years ago
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    who?

  43. anonymous
    • 4 years ago
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    the poster

  44. anonymous
    • 4 years ago
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    my screen frozed. i suppose i will mull it over. or just hope there will be no trig sub integrals.

  45. anonymous
    • 4 years ago
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    pray hard :D

  46. anonymous
    • 4 years ago
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    lol, yeh man just pray hard. go get some sleep so u can write the exam 2morrow

  47. anonymous
    • 4 years ago
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    hahaha thanks

  48. anonymous
    • 4 years ago
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    np

  49. razor99
    • 4 years ago
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    http://www.numberempire.com/integralcalculator.php

  50. razor99
    • 4 years ago
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    this might help ya linhong10

  51. anonymous
    • 4 years ago
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    lol razor u r the best

  52. razor99
    • 4 years ago
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    why?

  53. anonymous
    • 4 years ago
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    cuz u r always so helpful

  54. razor99
    • 4 years ago
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    thax i love to help people even i dont know it.

  55. razor99
    • 4 years ago
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    by the way i alway help my friends

  56. anonymous
    • 4 years ago
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    coool

  57. anonymous
    • 4 years ago
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    keep up the great work =)

  58. razor99
    • 4 years ago
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    rld u might be tired

  59. anonymous
    • 4 years ago
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    hehe never tired

  60. razor99
    • 4 years ago
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    wow ur so patient i hope .

  61. razor99
    • 4 years ago
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    someday i might be like u

  62. razor99
    • 4 years ago
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    i mean a being very patient

  63. anonymous
    • 4 years ago
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    hehe

  64. anonymous
    • 4 years ago
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    cool free notes :D

  65. anonymous
    • 4 years ago
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    ya sals notes

  66. razor99
    • 4 years ago
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    bye guyz wont see till friday okay

  67. anonymous
    • 4 years ago
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    k bb

  68. anonymous
    • 4 years ago
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    hf

  69. razor99
    • 4 years ago
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    cya around later guyz the school has finally started

  70. anonymous
    • 4 years ago
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    kk

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