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anonymous
 4 years ago
Integral of (1/(1+y^2)^(3/2))dy???
anonymous
 4 years ago
Integral of (1/(1+y^2)^(3/2))dy???

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well do u wanna use u subsitution?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't really know. I tried to integrate by parts, but apparently it's wrong.. or I did it wrong.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well wrong according to what?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0according to wolframalpha lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u can get diff answers depending on the way u integrate but it is in reality all the sam answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think subsitution is easier

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, they put y=tanu and then they did something, but I don't understand it :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh they used trig subsitution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i guess u didnt learn that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya that wld be the simplest

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did u learn trig subsitution yet?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nope, never learned it. this is for my DE class :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k give me a sec to figure it out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am getting an ugly one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have to use trig substitution... take a look at this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya but he never learnt that yet

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is this for hmw? or you are just doing problems for fun?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yah, i read that.. but how does sec^3(tan^1) = cos??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have an exam tomoroww lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok I will show u what i got. u = 1+y^2 du=2ydy (1/2)du=ydy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so (1/2) integral (u)^(2/3)(u1)^(1/2)du

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry i just dont know how to use latex

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0rld did you get a solution in the end using ur way?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well look at the solution you know how y=tanu , the solution says that at the begining? you substitute y= tanu, then u=tan1y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya sal's method will give u a nice answer and it is the simplest

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and \[\sin^2u+\cos^2u=1\] divide all by \[\cos^2u\] you will get, \[\tan^2u+1=\sec^2u\] you gotta know these identities

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol the guy disappeared

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0amma disappear too...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my screen frozed. i suppose i will mull it over. or just hope there will be no trig sub integrals.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol, yeh man just pray hard. go get some sleep so u can write the exam 2morrow

razor99
 4 years ago
Best ResponseYou've already chosen the best response.0this might help ya linhong10

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol razor u r the best

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cuz u r always so helpful

razor99
 4 years ago
Best ResponseYou've already chosen the best response.0thax i love to help people even i dont know it.

razor99
 4 years ago
Best ResponseYou've already chosen the best response.0by the way i alway help my friends

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0keep up the great work =)

razor99
 4 years ago
Best ResponseYou've already chosen the best response.0wow ur so patient i hope .

razor99
 4 years ago
Best ResponseYou've already chosen the best response.0someday i might be like u

razor99
 4 years ago
Best ResponseYou've already chosen the best response.0i mean a being very patient

razor99
 4 years ago
Best ResponseYou've already chosen the best response.0bye guyz wont see till friday okay

razor99
 4 years ago
Best ResponseYou've already chosen the best response.0cya around later guyz the school has finally started
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