Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

let S be the part of the surface z=4-x^2-y^2 that is above z=0. then the value of ln(doubleintegral:(z+2)dS) is:

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- chestercat

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

i think you need to use spherical coordinates,

- anonymous

help.

- dumbcow

ok i think i can set it up for you:
to determine the bounds of the integral use the inequality:
4-x^2 -y^2 > 0
y^2 < 4-x^2
-sqrt(4-x^2) < y < sqrt(4-x^2)
Domain inside radical must be positive:
4-x^2 > 0
x^2 < 4
-2 < x < 2
\[\large \int\limits_{-2}^{2}\int\limits_{-\sqrt{4-x^{2}}}^{\sqrt{4-x^{2}}} (6 -x^{2} -y^{2}) dy dx\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Actually, That may just help!,
can i go 4* the integrand and go from 0-->sqrt{4-x^2}and 0--->2

- anonymous

..instead?

- anonymous

by symmetry? i'm just trying to save myself a tiny bit of work, but i guess i can just try crunch it out

- dumbcow

yep...good idea

- anonymous

Darn, that still didn't work.

- dumbcow

what didn't work...not the right answer?
i get 16pi...so ln(16pi) = 3.917 ??

- anonymous

yeah, that's what I got as well
I'm given 8 possible decimal numbers as a solution and unfortunately that isn't one of them

- dumbcow

oh ok sorry i checked it again and it seems correct to me but im not an expert when it comes to surface integrals

- anonymous

Yes and it makes sense to me too, however we must be missing something here. If only that were clear. Thank you much for your efforts

- dumbcow

hey i found something
try 132.598
http://tutorial.math.lamar.edu/Classes/CalcIII/SurfaceIntegrals.aspx
http://www.wolframalpha.com/input/?i=integrate+4*%286-x%5E2+-y%5E2%29sqrt%284x%5E2%2B4y%5E2+%2B1%29+dydx+from+y%3D0+to+sqrt%284-x%5E2%29+and+x%3D0+to+2

- anonymous

ln(132.598)=4.88732
This IS one of the answers which means it is correct because all the others are there to prevent guessing!
I've seen Paul's notes before, and although they are helpful I was never able to put the full solution together!
Thank you alot!

Looking for something else?

Not the answer you are looking for? Search for more explanations.