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sima_zhao
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can anyone help me figure out a new equation for an ellipse whose length and width are doubled and the original equation is x^2/50+y^2/20=1
 2 years ago
 2 years ago
sima_zhao Group Title
can anyone help me figure out a new equation for an ellipse whose length and width are doubled and the original equation is x^2/50+y^2/20=1
 2 years ago
 2 years ago

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KDroid Group TitleBest ResponseYou've already chosen the best response.0
Find out a & b. Multiply them with 2. & put'em in the general equation of the ellipse. :)
 2 years ago

CynosureEPR Group TitleBest ResponseYou've already chosen the best response.0
KDroid is correct, but I'll give you a bit more: You want to take the square root of the numbers in the denominator of the 'x' and 'y' slots to get 'a' and 'b' (so 50 and 20 respectively; square root to get a=7.07 and b =4.46). That will give you the points on the xaxis and yaxis of which your ellipse crosses. Double this number and resquare it to get it back in the form you started in. So, \[\sqrt{50} = 7.07\] \[7.0*2 = 14.1421\] \[14.1421^{2} = 200\] 200 is the new value under your 'x'. Do the same for the 'y' and you should get 80.
 2 years ago
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