A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
A block with mass of 0.5 kg is forced against a horizontal spring of negligible mass. compressing the spring a distance of 0.20m. When released, the block moves on a horizontal tabletop for 1 meter before coming to rest. The spring constant is 100N/m. What is the coefficient of friction between the block and the tabletop??
anonymous
 4 years ago
A block with mass of 0.5 kg is forced against a horizontal spring of negligible mass. compressing the spring a distance of 0.20m. When released, the block moves on a horizontal tabletop for 1 meter before coming to rest. The spring constant is 100N/m. What is the coefficient of friction between the block and the tabletop??

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first calculate the potential energy stored in the spring. which is \[1/2kx^{2}\] . when the block is in rest it has zero mechanical energy,this means friction has done work equal to that of initial potential energy. therefore, F(friction) x X(distance moved) = \[1/2kx^{2}\] uN x 1 = 2 u = 2/5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0friction foced on block,lonely, when it separeted from spring :\[\mu _{s}mg=ma\] i think we use conservation energy between two points: where spring is completly compressed & when block release from it,so yields: \[(1/2)kx ^{2}=(1/2)mv ^{2}\] from above obtained v^2. (this (v) change to v0 for the next part of motion) independent equation of motion yeild's a : \[v ^{2}v _{0}^{2}=2ax\] at rest v=0 so \[a=v _{0}^{2}/2x\](x=1,according to ask) now if insert "a" in newton 2nd law \[\mu _{s}\] equals to 0.4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry \[\mu _{k}\] is correct, not \[\mu _{s}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.