nath
Find the measure of angle phi in degrees and the length of segment x in centimeters.
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Directrix
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Diagram?
nath
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SRRY I HAV AM DRAWING IT
nath
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|dw:1327994270675:dw|
Directrix
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If the dashed segment is an altitude or an angle bisector of the equilateral triangle, the "mystery" angle has measure 30.
nath
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|dw:1327994428232:dw| HERES A BETTER PICTURE
atjari
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theta is 30 degrees and x=7cm
nath
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CAN YOU PLEASE EXPLAIN HOW YOU CAME UP WITH THESE VALUES
Directrix
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What are you given about the dashed segment? Then, I can tell you.
nath
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Dividing an equilateral triangle in half leads to the next special triangle that we will look at. Consider the figure showing an equilateral triangle with a line dividing it down the middle. This line divides both the angle at the top of the triangle and the base of the triangle into two equal parts.
Directrix
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@ nath, how do you know that the equilateral triangle has been "halved?"
nath
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it was given with the question
Directrix
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@Cyno How do you know "since that angle is cut directly in half to ..?" Where is it given?
atjari
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cos60=x/14
1/2=x/14
x=7
90+60+theta=180
theta=30
nath
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thank you
Directrix
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|dw:1327994931350:dw|
atjari
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yw
Directrix
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Trig is not required. Use the 30-60-90 Theorem. b = 7 times square root 3.
nath
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for some reason that isnt the answer
Directrix
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@ Nath 7 times square root 3
nath
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x =7
Directrix
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7 times square root(3) = 12.1243557
nath
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i got that but the answer for x is x=7
Directrix
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x=7. 7times square root 3 is the length of the altitude (dashed segment on drawing which everyone but me knows intersects at a right angle :))
nath
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i still do not understand how x=7 still . after we found that the value is about 12 how do we go from 12 to 7
atjari
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c=14
so c^2=14^2
nath
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so is this what you all mean b^2+ (7)^2=(14)^2
nath
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right but atjari said c=14 thats why im confused.. you said c^2=14