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SRRY I HAV AM DRAWING IT
If the dashed segment is an altitude or an angle bisector of the equilateral triangle, the "mystery" angle has measure 30.
|dw:1327994428232:dw| HERES A BETTER PICTURE
theta is 30 degrees and x=7cm
CAN YOU PLEASE EXPLAIN HOW YOU CAME UP WITH THESE VALUES
What are you given about the dashed segment? Then, I can tell you.
Dividing an equilateral triangle in half leads to the next special triangle that we will look at. Consider the figure showing an equilateral triangle with a line dividing it down the middle. This line divides both the angle at the top of the triangle and the base of the triangle into two equal parts.
@ nath, how do you know that the equilateral triangle has been "halved?"
it was given with the question
@Cyno How do you know "since that angle is cut directly in half to ..?" Where is it given?
cos60=x/14 1/2=x/14 x=7 90+60+theta=180 theta=30
Trig is not required. Use the 30-60-90 Theorem. b = 7 times square root 3.
for some reason that isnt the answer
@ Nath 7 times square root 3
7 times square root(3) = 12.1243557
i got that but the answer for x is x=7
x=7. 7times square root 3 is the length of the altitude (dashed segment on drawing which everyone but me knows intersects at a right angle :))
i still do not understand how x=7 still . after we found that the value is about 12 how do we go from 12 to 7
c=14 so c^2=14^2
so is this what you all mean b^2+ (7)^2=(14)^2
right but atjari said c=14 thats why im confused.. you said c^2=14