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I gues you know what to do with the denominator?
yes im stuck at this part 2x - 1 2x + 5 ------------- - ------------- (2x + 5)(2x - 5) (2x - 1)(2x + 5) What do i do after?
What can you cross out now?
well the 2x - 1 on the right side (denominator)
i just dont get what to multiply the numerator with
Well, the denominators are the same now.
What does that mean you can do?
can you like stop giving me hints. I am already stressed out and i know i did this before. Show me the steps after the part i gave and to the correct answer. Would appreciate it
Tim's actually guiding you to solve the problem. He's cool.
i understand alright but i just wanna know the steps kay. I have an exam in 7 hours
I am a cool Tim.
But if you can't do this yourself, then what's the point of reviewing.
So, what's your next step, with the knowledge that the denoms are the same.
i did this before that's what im saying . I got stuck on this part.
what kind of equation is that dada
Ok. So what are you doing now.
all im asking is that do you multiply the numerators by all the denominators eg. (2x - 1) (2x + 5)
or just one denominator and yes razor this is algebra
common denominator will be (2x+5)(2x-5)(2x-1) (2x-1)^2-(2x+5)(2x-5)/ (2x+5)(2x-5)(2x-1) 4x^2-4x+1-4x^2+25/(2x+5)(2x-5)(2x-1) 26-4x/(2x+5)(2x-5)(2x-1)
That person is right.
the numerator should be -2(10x - 13)
Multiply the top left by 2x - 1. Multiply the top right by 2x - 5
that link might help ya
did u went to that link dada.
yeah but i just wanna know that one step. Im on it now to see if my problem is solved
you have to buy the step by step solutions....forget it
this will show u all the steps go to go to school byeee.
with which step r u having problem?
i am having trouble with the step when you multiply the numerators with the common denominator
R u k with finding the common denominator?
yeah i understand that part. Just not the part where you're multiplying
2x - 1 2x + 5 ------------- - ------------- (2x + 5)(2x - 5) (2x - 1)(2x + 5) |dw:1327997865165:dw|
u hav (2x+5)(2x-5) as the denominator of the 1st part. the common denominator is (2x+5)(2x-5)(2x-1). u havnt nly 2x-1 in the 1st part but which u hav in the common denominator. so multiply the numerator of the 1st nly by 2x-1.
Can you handle it from there?\
The denominators are the same
Now you just need to combine into one fraction keeping the denominator the same
R u clear nw?
The final simplification is a mess.