Simplify:
2x - 1 2x + 5
-------- - -------
4x^2 -25 4x^2 - 8x -5

- anonymous

Simplify:
2x - 1 2x + 5
-------- - -------
4x^2 -25 4x^2 - 8x -5

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- IsTim

I gues you know what to do with the denominator?

- anonymous

yes im stuck at this part
2x - 1 2x + 5
------------- - -------------
(2x + 5)(2x - 5) (2x - 1)(2x + 5)
What do i do after?

- IsTim

What can you cross out now?

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## More answers

- anonymous

well the 2x - 1 on the right side (denominator)

- anonymous

i just dont get what to multiply the numerator with

- IsTim

Well, the denominators are the same now.

- IsTim

What does that mean you can do?

- anonymous

can you like stop giving me hints. I am already stressed out and i know i did this before. Show me the steps after the part i gave and to the correct answer. Would appreciate it

- anonymous

LOL harrassment

- anonymous

Tim's actually guiding you to solve the problem. He's cool.

- anonymous

i understand alright but i just wanna know the steps kay. I have an exam in 7 hours

- IsTim

I am a cool Tim.

- IsTim

ME too!

- IsTim

But if you can't do this yourself, then what's the point of reviewing.

- IsTim

So, what's your next step, with the knowledge that the denoms are the same.

- anonymous

i did this before that's what im saying . I got stuck on this part.

- razor99

what kind of equation is that dada

- IsTim

Ok. So what are you doing now.

- anonymous

all im asking is that do you multiply the numerators by all the denominators
eg. (2x - 1) (2x + 5)

- razor99

an algebra

- anonymous

or just one denominator and yes razor this is algebra

- anonymous

common denominator will be (2x+5)(2x-5)(2x-1)
(2x-1)^2-(2x+5)(2x-5)/ (2x+5)(2x-5)(2x-1)
4x^2-4x+1-4x^2+25/(2x+5)(2x-5)(2x-1)
26-4x/(2x+5)(2x-5)(2x-1)

- IsTim

That person is right.

- anonymous

the numerator should be -2(10x - 13)

- razor99

http://www.myalgebra.com/algebra_solver.aspx

- IsTim

Multiply the top left by 2x - 1. Multiply the top right by 2x - 5

- razor99

that link might help ya

- razor99

did u went to that link dada.

- anonymous

yeah but i just wanna know that one step. Im on it now to see if my problem is solved

- razor99

okay.

- anonymous

you have to buy the step by step solutions....forget it

- razor99

http://www.algebrahelp.com/calculators/equation/

- razor99

this will show u all the steps go to go to school byeee.

- anonymous

with which step r u having problem?

- anonymous

mohamed?

- anonymous

i am having trouble with the step when you multiply the numerators with the common denominator

- anonymous

R u k with finding the common denominator?

- anonymous

yeah i understand that part. Just not the part where you're multiplying

- Hero

2x - 1 2x + 5
------------- - -------------
(2x + 5)(2x - 5) (2x - 1)(2x + 5)
|dw:1327997865165:dw|

- anonymous

u hav (2x+5)(2x-5) as the denominator of the 1st part. the common denominator is (2x+5)(2x-5)(2x-1). u havnt nly 2x-1 in the 1st part but which u hav in the common denominator. so multiply the numerator of the 1st nly by 2x-1.

- Hero

|dw:1327998038832:dw|

- Hero

|dw:1327998206040:dw|

- Hero

|dw:1327998321507:dw|

- Hero

Can you handle it from there?\

- Hero

The denominators are the same

- Hero

Now you just need to combine into one fraction keeping the denominator the same

- anonymous

R u clear nw?

- Hero

The final simplification is a mess.

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