Here's the question you clicked on:
merlynn
Consider the following linear equation: 1/8(z+3)=4/5(z+1/8) Solve the above linear equation. Simplify your answer.
I've gotcha! ..just let me type it all out.
if you want to get rid of the fractions, you can multiply the equation by 40 -> 5(z+3) = 32(z+ 1/8)
Okay, I hope you can read this: First, simplify the equations: \[1/8(z) + 3/8 = 4/5(z) + 4/40\] Next, collect like-terms (z's) on one side of the equation: \[1/8(z) - 4/5(z) = 4/40 - 3/8\] Multiply through to get a common denominator (of 40): \[5/40(z) - 32/40(z) = 4/40 - 15/40\] Simplify each side by subtracting the like terms on each side: \[-27/40z = -11/40\] Divide the -27/40 into -11/40, or multiply by the reciprocal: \[z = (-11/40) * (40/-27)\] ..and there you have it. z = -11/-27 or just 11/27.