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anonymous

  • 4 years ago

please help! What is the slope of a line that passes through the point (-2, 3) and is parallel to a line that passes through (3, 7) and (-2, -8)?

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  1. anonymous
    • 4 years ago
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    =-8-7/-2-3 =-15/-3 =5

  2. anonymous
    • 4 years ago
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    \[{ (-8-7) \over (-2-3) }= 5\] This will be slope of the every parallel line, that is parallel to this line.

  3. anonymous
    • 4 years ago
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    the equation of the line form is: y-3=5(x+2) y-3=5x+10 5x-y+13=0

  4. anonymous
    • 4 years ago
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    I like you name haha_proof :D

  5. anonymous
    • 4 years ago
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    thanks..im not really good in math as you think..

  6. anonymous
    • 4 years ago
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    Thanks for all of your help :) and thank you :D

  7. anonymous
    • 4 years ago
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    Glad to help :)

  8. anonymous
    • 4 years ago
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    can you please help with one more im doing this exam and im so lost on these type of problems and i have to get a good grade.?

  9. anonymous
    • 4 years ago
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    you're welcome ...its our pleasure to solve math problems,hehe

  10. anonymous
    • 4 years ago
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    What is the slope of the line passing through the point (3, -4) and perpendicular to the line y = 3x + 5? Write your answer as a fraction.

  11. anonymous
    • 4 years ago
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    what you are going to do is that familiarize the different form of the line equation.

  12. anonymous
    • 4 years ago
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    y=3x+5 is in the form of slope intercept form where y=mx +b. so the slope is m=3. to get perpendicular slope of the given line you need to get the multiplicative inverse that will result to -1 so the slope is m=-1/3

  13. anonymous
    • 4 years ago
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    Thank you for all of your help :) im still a little confused but ill try my next problem on own!

  14. anonymous
    • 4 years ago
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    *my own

  15. anonymous
    • 4 years ago
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    ok,just remember that parallel lines do have the same slope and perpendicular lines get -1 if slopes are to be multiplied.

  16. anonymous
    • 4 years ago
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    ok thanks again!

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