Two buses leaves the terminal at the same time. One heads due east at 25 kph and one heads due north at 40 kph. See figure (a) below. How far apart are the two buses after 2 hours?

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Two buses leaves the terminal at the same time. One heads due east at 25 kph and one heads due north at 40 kph. See figure (a) below. How far apart are the two buses after 2 hours?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Are you going to post figure (a)?
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Thanks

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Other answers:

there it is
So, how far have you got by yourself?
("no idea" is fine too btw)
idk
|dw:1328010806645:dw|
i really dont know
Have you heard of pythagoras's theorem?
c^2 = 50^2 + 80^2 c^2 = 2500 + 6400 c^2 = 8900 c = sqrt( 8900 ) c= 94,34
Well, he's given you the answer now. Do you want me to work through it with you or did you just want the answer?
Well, in two hours one bus has gone east by 25x2=50km, while the other has gone north by 40x2=80km. To find the (shortest) distance between them x, we use mythagoras: \[x = \sqrt{50^2 + 80^2} = \sqrt{2500 + 6400} = \sqrt{8900} = 94.3398km\]
Alynaanalise are you still there?
Pythagoras* lol
Nice, you can't even give the medal to the right answer, no wonder you can't figure out pythagoras....
lol...frustrating...close to level 30?
anyways, thanks
can you please help me answer this one;: its a figure
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