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anonymous

  • 4 years ago

Two buses leaves the terminal at the same time. One heads due east at 25 kph and one heads due north at 40 kph. See figure (a) below. How far apart are the two buses after 2 hours?

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  1. anonymous
    • 4 years ago
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    Are you going to post figure (a)?

  2. anonymous
    • 4 years ago
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  3. anonymous
    • 4 years ago
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    Thanks

  4. anonymous
    • 4 years ago
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    there it is

  5. anonymous
    • 4 years ago
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    So, how far have you got by yourself?

  6. anonymous
    • 4 years ago
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    ("no idea" is fine too btw)

  7. anonymous
    • 4 years ago
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    idk

  8. anonymous
    • 4 years ago
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    |dw:1328010806645:dw|

  9. anonymous
    • 4 years ago
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    i really dont know

  10. anonymous
    • 4 years ago
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    Have you heard of pythagoras's theorem?

  11. anonymous
    • 4 years ago
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    c^2 = 50^2 + 80^2 c^2 = 2500 + 6400 c^2 = 8900 c = sqrt( 8900 ) c= 94,34

  12. anonymous
    • 4 years ago
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    Well, he's given you the answer now. Do you want me to work through it with you or did you just want the answer?

  13. anonymous
    • 4 years ago
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    Well, in two hours one bus has gone east by 25x2=50km, while the other has gone north by 40x2=80km. To find the (shortest) distance between them x, we use mythagoras: \[x = \sqrt{50^2 + 80^2} = \sqrt{2500 + 6400} = \sqrt{8900} = 94.3398km\]

  14. anonymous
    • 4 years ago
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    Alynaanalise are you still there?

  15. anonymous
    • 4 years ago
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    Pythagoras* lol

  16. anonymous
    • 4 years ago
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    Nice, you can't even give the medal to the right answer, no wonder you can't figure out pythagoras....

  17. anonymous
    • 4 years ago
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    lol...frustrating...close to level 30?

  18. anonymous
    • 4 years ago
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    anyways, thanks

  19. anonymous
    • 4 years ago
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    can you please help me answer this one;: its a figure

  20. anonymous
    • 4 years ago
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