## anonymous 4 years ago Two buses leaves the terminal at the same time. One heads due east at 25 kph and one heads due north at 40 kph. See figure (a) below. How far apart are the two buses after 2 hours?

1. anonymous

Are you going to post figure (a)?

2. anonymous

3. anonymous

Thanks

4. anonymous

there it is

5. anonymous

So, how far have you got by yourself?

6. anonymous

("no idea" is fine too btw)

7. anonymous

idk

8. anonymous

|dw:1328010806645:dw|

9. anonymous

i really dont know

10. anonymous

Have you heard of pythagoras's theorem?

11. anonymous

c^2 = 50^2 + 80^2 c^2 = 2500 + 6400 c^2 = 8900 c = sqrt( 8900 ) c= 94,34

12. anonymous

Well, he's given you the answer now. Do you want me to work through it with you or did you just want the answer?

13. anonymous

Well, in two hours one bus has gone east by 25x2=50km, while the other has gone north by 40x2=80km. To find the (shortest) distance between them x, we use mythagoras: $x = \sqrt{50^2 + 80^2} = \sqrt{2500 + 6400} = \sqrt{8900} = 94.3398km$

14. anonymous

Alynaanalise are you still there?

15. anonymous

Pythagoras* lol

16. anonymous

Nice, you can't even give the medal to the right answer, no wonder you can't figure out pythagoras....

17. anonymous

lol...frustrating...close to level 30?

18. anonymous

anyways, thanks

19. anonymous

20. anonymous

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