anonymous
  • anonymous
Two buses leaves the terminal at the same time. One heads due east at 25 kph and one heads due north at 40 kph. See figure (a) below. How far apart are the two buses after 2 hours?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Are you going to post figure (a)?
anonymous
  • anonymous
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anonymous
  • anonymous
Thanks

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anonymous
  • anonymous
there it is
anonymous
  • anonymous
So, how far have you got by yourself?
anonymous
  • anonymous
("no idea" is fine too btw)
anonymous
  • anonymous
idk
anonymous
  • anonymous
|dw:1328010806645:dw|
anonymous
  • anonymous
i really dont know
anonymous
  • anonymous
Have you heard of pythagoras's theorem?
anonymous
  • anonymous
c^2 = 50^2 + 80^2 c^2 = 2500 + 6400 c^2 = 8900 c = sqrt( 8900 ) c= 94,34
anonymous
  • anonymous
Well, he's given you the answer now. Do you want me to work through it with you or did you just want the answer?
anonymous
  • anonymous
Well, in two hours one bus has gone east by 25x2=50km, while the other has gone north by 40x2=80km. To find the (shortest) distance between them x, we use mythagoras: \[x = \sqrt{50^2 + 80^2} = \sqrt{2500 + 6400} = \sqrt{8900} = 94.3398km\]
anonymous
  • anonymous
Alynaanalise are you still there?
anonymous
  • anonymous
Pythagoras* lol
anonymous
  • anonymous
Nice, you can't even give the medal to the right answer, no wonder you can't figure out pythagoras....
anonymous
  • anonymous
lol...frustrating...close to level 30?
anonymous
  • anonymous
anyways, thanks
anonymous
  • anonymous
can you please help me answer this one;: its a figure
anonymous
  • anonymous
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