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but yar salini we were told na dat io means branching from second carbon and here neo i also occurig i m confused in this str.
do any one have reaon y this str. i like thsi?? y cant like this?|dw:1109455489640:dw| i didnt join H its known ok i think no need to represent here
say y cant str. like this??
Iso- can be used for substituents that branch at the second-to-last carbon and end with two methyl group not one
i agreee but there is neo also wat u wanna say abu that and my str. is not wrong then??
|dw:1328015856402:dw|Neo- refers to a substituent whose second-to-last carbon of the chain is trisubstituted (has three methyl groups attached to it).
this are all applicable for functional groups like alcohol,ketone etc that i swhy it is the 2nd carbon as functional group is given importannce while naming
who ay thi thing to u that second carbon is impt while naming its wrong... dont say in exam u ll get zero
the functional group is given importance not the 2nd carbon while naming
yea but here no funtional group can be identify its alkane?? u read hydrocarbons??
leave it salini i ll learn it :P enjoy
hey i figured it out at last..... first we draw the 2nd carbon at the end then a 1st carbon always start from right to left |dw:1328017579611:dw| when they say neo add 3 more carbons to that (supposed to be) 2nd carbon when it is iso add 2 carbons then dont dont 1st named carbon then count how many carbons has been used up by those 1st and second with regard to that add remaninig carbons with hydrogen in the place of R that i have written for example when u say neo-pentane first write down the 2nd and 1st carbon |dw:1328017794651:dw| DONT TOUCH 1ST CARBON later out of the 5 carbons available i used up 5 carbons so i dont have any more to fill instead of R if there are extra carbons after satisfying 1 and 2 JUST PUT THEM INSTEAD OF R it works for almost everything i tried
thnx..but i think we have to learn this hain na??mene to yad kr liya :P