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-48 ÷ (7 – 9)^3 – 2[1 – 5(2 – 6) + 3^2].

Mathematics
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Hey there, Just remember to "break up" the problem into smaller parts in order to solve it: For instance: -48 is one part.. (7-9)^3 is another that simply equals (-2)^3, or -8 So now you have: -48/8..which is -6 Then go inside your []: 2-6 is -3, times 5 is -15 So now you have: -6 - 2[1-(-15)+3^2] 1 minus -15 is 16.. 3^2 is 9, and 16+9 is 25. so now you have: -6 - 2[25] 2 times 25 is 50, so now you have -6 - 50 which is -56.
thanks i have been trying to solve this problem for 3 days now
You're very welcome! ..and remember, divide and conquer!

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