## anonymous 4 years ago http://i729.photobucket.com/albums/ww292/akatushi101/algeeeeeeeeeee.jpg I need help on the Four questions .

1. anonymous

=) Give me just a minute to write them down and snap a pic.

2. anonymous

Okay :)

3. anonymous

also these are Matrices

4. lalaly

$\left[\begin{matrix}2 & 3 \\ 5 & 1\end{matrix}\right]-\left[\begin{matrix}-1 & 7 \\ 9 & 8\end{matrix}\right]=\left[\begin{matrix}2-(-1) & 3-7 \\ 5-9 & 1-8\end{matrix}\right]=\left[\begin{matrix}3 & -4 \\ -4 & -7\end{matrix}\right]$

5. anonymous

Are the first/third ones division or addition?

6. anonymous

7. anonymous

Thanks!

8. lalaly

oh u do the same, just change the minus sign to plus

9. anonymous

10. anonymous

Here you go (the first problem is last, because I thought it was a division sign!) http://postimage.org/image/kmf3y8d8n/

11. anonymous

oh okay thanks !

12. anonymous

You're welcome!

13. anonymous

why is the third problem not possible?

14. anonymous

Because the two matrices are of different dimensions. If you go ahead and try to attempt it, you'll see quickly that you've run out of numbers and have two left over. It simply doesn't work. =)

15. anonymous

I have three questions left from this matrice ..can you help me :S?

16. anonymous

Sure thing!

17. anonymous
18. anonymous

the 6th question there is no "-" or " + " so i think we can not operate it?

19. anonymous

That would assume that you multiply them.

20. anonymous

but it is set like this [ 1 2 ][1] [3 7] [5]

21. anonymous

It's uploading! You can only multiply matrices if the rows of the first equals the columns of the second. Basically, how that works is you take the terms as such: [ a b ] [1] [ c d ] [5] so that the new matrix is: [ a*1 + b*5 ] [ c*1 + d*5 ]

22. anonymous

Here ya go: http://postimage.org/image/p1sw2isxt/

23. anonymous

oh okay.

24. anonymous

Do you understand?

25. anonymous

Yes.. :) I'm sorry these were the last ones. . these are the last remaining problems http://i729.photobucket.com/albums/ww292/akatushi101/ALGEE222.jpg

26. anonymous

I'm sorry, but I have to head off to class now!=( You can try re-posting the new set for someone else to answer or wait a few hours for my response.

27. anonymous

okay thanks for all the help!