anonymous
  • anonymous
ABE+ACE+ADE=2012 What number represents which letter?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
E = 4
vishal_kothari
  • vishal_kothari
it has infinitely many solution....
anonymous
  • anonymous
But every cryptogram has a unique solution right?

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anonymous
  • anonymous
no it's certainly don't have infinitely solutions
vishal_kothari
  • vishal_kothari
the set of numbers are not given ....
anonymous
  • anonymous
and letters can represent only 1 digit
vishal_kothari
  • vishal_kothari
so sorry..i got it...i thought we considered each as a single variable....
anonymous
  • anonymous
A=6 E=4 B+C+D=20 so you can choose any numbers e.g. B=2 C=9 D=9
radar
  • radar
or b=7, c=5, d=8
anonymous
  • anonymous
Thank you everyone :)
anonymous
  • anonymous
i am willing to bet you are making the assumption (though not stated) that different letters represent different numbers, so i would go with radar's answer
anonymous
  • anonymous
Unfortunately not, I'll take the A + B + C + D + E and then the answer is the number I need. :)
phi
  • phi
assuming each letter represents a distinct digit, there are two triplets that satisfy the condition 634,684,694 and 654,674,684
anonymous
  • anonymous
so you should have stated at the beginning that you need to find A+B+C+D+E
anonymous
  • anonymous
No, why should I? Once I got help with the letters, it was not so hard to plus them together.
anonymous
  • anonymous
because it would be easier to solve it
anonymous
  • anonymous
No, it would not make any difference.
anonymous
  • anonymous
well i have solved it, so i can say that it would be easier :P
anonymous
  • anonymous
also there might be such problems that you can't get answers to all parts only sum of them so better post full question
phi
  • phi
@97 I agree with Tomas, it is much easier to find the sum of A,B,C,D,E than to find all permutations. Why don't you try for yourself and see.
anonymous
  • anonymous
But I needed two responses, and the last one I could actually figure out myself.

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