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anonymous

  • 4 years ago

ABE+ACE+ADE=2012 What number represents which letter?

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  1. anonymous
    • 4 years ago
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    E = 4

  2. vishal_kothari
    • 4 years ago
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    it has infinitely many solution....

  3. anonymous
    • 4 years ago
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    But every cryptogram has a unique solution right?

  4. anonymous
    • 4 years ago
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    no it's certainly don't have infinitely solutions

  5. vishal_kothari
    • 4 years ago
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    the set of numbers are not given ....

  6. anonymous
    • 4 years ago
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    and letters can represent only 1 digit

  7. vishal_kothari
    • 4 years ago
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    so sorry..i got it...i thought we considered each as a single variable....

  8. anonymous
    • 4 years ago
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    A=6 E=4 B+C+D=20 so you can choose any numbers e.g. B=2 C=9 D=9

  9. radar
    • 4 years ago
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    or b=7, c=5, d=8

  10. anonymous
    • 4 years ago
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    Thank you everyone :)

  11. anonymous
    • 4 years ago
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    i am willing to bet you are making the assumption (though not stated) that different letters represent different numbers, so i would go with radar's answer

  12. anonymous
    • 4 years ago
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    Unfortunately not, I'll take the A + B + C + D + E and then the answer is the number I need. :)

  13. phi
    • 4 years ago
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    assuming each letter represents a distinct digit, there are two triplets that satisfy the condition 634,684,694 and 654,674,684

  14. anonymous
    • 4 years ago
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    so you should have stated at the beginning that you need to find A+B+C+D+E

  15. anonymous
    • 4 years ago
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    No, why should I? Once I got help with the letters, it was not so hard to plus them together.

  16. anonymous
    • 4 years ago
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    because it would be easier to solve it

  17. anonymous
    • 4 years ago
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    No, it would not make any difference.

  18. anonymous
    • 4 years ago
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    well i have solved it, so i can say that it would be easier :P

  19. anonymous
    • 4 years ago
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    also there might be such problems that you can't get answers to all parts only sum of them so better post full question

  20. phi
    • 4 years ago
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    @97 I agree with Tomas, it is much easier to find the sum of A,B,C,D,E than to find all permutations. Why don't you try for yourself and see.

  21. anonymous
    • 4 years ago
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    But I needed two responses, and the last one I could actually figure out myself.

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