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anonymous
 4 years ago
integrate x^33^x dx
anonymous
 4 years ago
integrate x^33^x dx

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0product of x raised to power three and 3 raised to power x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i assume this is \[\int x^33^xdx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is a set up for integration by parts, but you have to do it 3 times ! will reduce the power on \[x^3\] once each time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have assumed f(x)=x^3 and g'(x)=3^x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for example in the first time you will put \[u=x^3, dv=3^xdx, du=3x^2,v=\frac{3^x}{\ln(3)}\] and get \[uv\int vdu=\frac{x^33^x}{\ln(3)}\frac{3}{\ln(3)}\int x^23^xdx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then lather, rinse, repeat. hold on

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0easier to read it , click "show steps" http://www.wolframalpha.com/input/?i=x^3*3^x+dx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would u integrate 3x^2.3^x/log3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first of all pull out the constants like i did above and get \[\frac{3}{\ln(3)}\int x^23^xdx\] then repeat the parts, this time with \[u=x^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ur ans went over my head

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok it is confusing, but if you got the first one right you should have a good idea what is going on each time you integrate by parts, you will reduce the power by one when you take the derivative of \[x^3, x^2, x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0don't forget that \[\ln(3)\] is a number (constant) so it come right out front of the integral sign

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your next job is really \[\int x^2 3^xdx\] the constant just sits out front. integrate by parts again

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let me show u the first step......3x^2.3x/log3integrate3x^2.3^x/log3 dx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah first step is wrong that is the problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is \[\int udv=uv\int vdu\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dnt use that formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[u=x^3,du = 3x^2, dv = 3^x, v = \int 3^x=\frac{3^x}{\ln(3)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[uv=\frac{x^33^x}{\ln(3)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and i stress again, even though the second one is \[\int \frac{3x^23^x}{\ln(3)}dx\] you should rewrite it immediately as \[\frac{3}{\ln(3)}\int x^23^xdx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i m having trouble with the formula implementation......wht to do?
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