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anonymous
 4 years ago
1. Find the general solution (or as close as you can come to it) for the following differential
equations, using separation of variables.
(a) dy/dt = 2y − 1
(b) dy/dt = t^2y^3
anonymous
 4 years ago
1. Find the general solution (or as close as you can come to it) for the following differential equations, using separation of variables. (a) dy/dt = 2y − 1 (b) dy/dt = t^2y^3

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0separation is just splitting up same variables on same sides

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{dy}{dt}=2y1\] \[dy=(2y1)dt\] \[(2y1)^{1}dy=dt\] \[\int((2y1)^{1}dy=dt)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the asnwer would be \[y=\sqrt[3]{pmAe^(t^3/3)}\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int((2y1)^{1}dy=dt)\] \[\frac{1}{2}ln2y1=t+C\] \[ln2y1=2t+C\] \[2y1=\pm C*exp(2t)\] \[y=\pm \frac{Ce^{2t}+1}{2}\] is what I get
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