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RagingSquirrel

  • 4 years ago

How many different ways are there to arrange the letters A, B, A, and B? 4 6 8 16

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  1. RagingSquirrel
    • 4 years ago
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    ABBA AABB BBAA BABA ABAB anything else?

  2. anonymous
    • 4 years ago
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    6

  3. ash2326
    • 4 years ago
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    Total no. of letters 4! no. of times A repeated 2! no.o times B repeated 2! so 4!/(2!*2!)= 24/4=6

  4. anonymous
    • 4 years ago
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    Infinite.

  5. campbell_st
    • 4 years ago
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    well I would have said 24 ways..... 4 choices for the 1st position, 3 choices for the 2nd , 2 choices for the 3rd position and only 1 choice for the 4th postion... 4 x 3 x 2 x 1 =24

  6. phi
    • 4 years ago
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    @raging BAAB is the 6th sequence @camp both A and B are repeated. when you write down BB that is only one combination. Your way will count it as 2.

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