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anonymous
 4 years ago
if f(x)= 4x^321x^2+36x4, then the graph of f is decreasing and concave up on the interval...
anonymous
 4 years ago
if f(x)= 4x^321x^2+36x4, then the graph of f is decreasing and concave up on the interval...

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would you like the choices?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a. (3/2, 2) b. (neg. infinity, 7/4) c. (7/4, infinity) d. (7/4, 2) e. (3/2, 7/4)

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.0Given f(x)= 4x^321x^2+36x4. The graph is decreasing when f'(x)<0. f'(x)=12x^242x+36 which factors into f'(x)=6(x2)(2x3). This means that f'(x) is negative (f(x) decreasing) between 1.5 and 2, or (1.5,2). For concavity, we look at f"(x)=24x42=6(4x7), which means that f(x) is concave up when x>7/4, or (7/4,+inf) Therefore f(x) is increasing and concave up between 7/4 and 2, or (7/4,2)
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