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anonymous

  • 4 years ago

The absolute maximum value of f(x)=x^3-3x^2+12 on [-2, 4] occurs at x=

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  1. anonymous
    • 4 years ago
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    0

  2. anonymous
    • 4 years ago
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    how?

  3. saifoo.khan
    • 4 years ago
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    That's Hard. D:

  4. anonymous
    • 4 years ago
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    thanks for trying :))

  5. saifoo.khan
    • 4 years ago
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    No problem. u may come here in a hour or two, user Myininya, Satellite, JamesJ and others are online. They can help u with this in Notime.

  6. anonymous
    • 4 years ago
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    alrighty :)

  7. saifoo.khan
    • 4 years ago
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    C ya, nice meeting u! [:

  8. anonymous
    • 4 years ago
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    pleasure was all mine :)

  9. saifoo.khan
    • 4 years ago
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    ;)

  10. anonymous
    • 4 years ago
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    x^3-3x^2+12 (1) first we determine the degree: (the maximum power at which x is raised::) => http://en.wikipedia.org/wiki/Polynomial#Graphs then we find the derivative => 3x^2-6x (2) then we see where (2) is zero /and we know that (1) has either a max, a min, or a change of heart there( see x^3) |dw:1328084114567:dw|

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spraguer (Moderator)
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