anonymous
  • anonymous
The absolute maximum value of f(x)=x^3-3x^2+12 on [-2, 4] occurs at x=
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
0
anonymous
  • anonymous
how?
saifoo.khan
  • saifoo.khan
That's Hard. D:

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anonymous
  • anonymous
thanks for trying :))
saifoo.khan
  • saifoo.khan
No problem. u may come here in a hour or two, user Myininya, Satellite, JamesJ and others are online. They can help u with this in Notime.
anonymous
  • anonymous
alrighty :)
saifoo.khan
  • saifoo.khan
C ya, nice meeting u! [:
anonymous
  • anonymous
pleasure was all mine :)
saifoo.khan
  • saifoo.khan
;)
anonymous
  • anonymous
x^3-3x^2+12 (1) first we determine the degree: (the maximum power at which x is raised::) => http://en.wikipedia.org/wiki/Polynomial#Graphs then we find the derivative => 3x^2-6x (2) then we see where (2) is zero /and we know that (1) has either a max, a min, or a change of heart there( see x^3) |dw:1328084114567:dw|

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