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anonymous

  • 4 years ago

Can someone tell me if I worked this problem out correctly: x^2-8x+3 = 0 1) x^2 - 8x + 16 = 13 (divided the 8 by 2, then took the square root of 4 and added it to both sides) 2) (x-4)^2 = 13 3) x -4 = +/- 13 4) x = 4+13 = 17 and x = 4-13 = -8 5) x = 17, -8

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  1. anonymous
    • 4 years ago
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    this is a "complete the square" problem.

  2. saifoo.khan
    • 4 years ago
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    seems wrong! D:

  3. anonymous
    • 4 years ago
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    where did I go wrong?

  4. Mertsj
    • 4 years ago
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    when you took the square root of the left side, you should also have taken the square root of the right side

  5. anonymous
    • 4 years ago
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    oops, the original problem was: x ^2 - 8x + 3 =0. I subtracted -3 from both sides. Then when I took the square root of 4, I added it to both sides. I forgot to show that in my problem.

  6. Mertsj
    • 4 years ago
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    |dw:1328050411905:dw|

  7. Mertsj
    • 4 years ago
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    You squared 4. You did not take the square root of 4. You added 4^2 to both sides and that was correct.

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