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anonymous

  • 4 years ago

find the derivative of x^3 at x=-2 algebraically, jot my memory, do you use f(x+h)-f(x)/h?

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  1. phi
    • 4 years ago
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    Unless you are deriving the various formulas, there is no reason to use the fundamental approach. Use the exponent rule: \[\frac{ d x^n}{dx}= n x^{n-1} \]

  2. phi
    • 4 years ago
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    once you have found the derivative, replace x with -2 and evaluate it to answer the question

  3. precal
    • 4 years ago
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    Use the power rule. Easiest rule in calculus to remember. By the way phi already stated it above.

  4. anonymous
    • 4 years ago
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    ok thank you soo, x^3 using the power rule, 3x^2 is the derivative, then plugging in x=-2 gives us 3(-2)^2=12?

  5. phi
    • 4 years ago
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    yes

  6. anonymous
    • 4 years ago
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    thank you phi and pre cal, im in calc 1 and it can be confusing at times, I guess the power rule is a lifesaver, much thanks

  7. precal
    • 4 years ago
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    use calculus notation for example y prime or f prime of x

  8. anonymous
    • 4 years ago
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    ok like this right f'(x)

  9. precal
    • 4 years ago
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    yes f'(-2)=12

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