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anonymous
 4 years ago
find the derivative of x^3 at x=2 algebraically, jot my memory, do you use f(x+h)f(x)/h?
anonymous
 4 years ago
find the derivative of x^3 at x=2 algebraically, jot my memory, do you use f(x+h)f(x)/h?

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phi
 4 years ago
Best ResponseYou've already chosen the best response.0Unless you are deriving the various formulas, there is no reason to use the fundamental approach. Use the exponent rule: \[\frac{ d x^n}{dx}= n x^{n1} \]

phi
 4 years ago
Best ResponseYou've already chosen the best response.0once you have found the derivative, replace x with 2 and evaluate it to answer the question

precal
 4 years ago
Best ResponseYou've already chosen the best response.0Use the power rule. Easiest rule in calculus to remember. By the way phi already stated it above.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thank you soo, x^3 using the power rule, 3x^2 is the derivative, then plugging in x=2 gives us 3(2)^2=12?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you phi and pre cal, im in calc 1 and it can be confusing at times, I guess the power rule is a lifesaver, much thanks

precal
 4 years ago
Best ResponseYou've already chosen the best response.0use calculus notation for example y prime or f prime of x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok like this right f'(x)
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