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anonymous

  • 4 years ago

Evaluate when t=1.5 [(t+2)squared-3t]/5 the answer is (t squared +t+4)/5 right?

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  1. precal
    • 4 years ago
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    are you just plugging in t=1.5? This sounds like particle motion (calculus and physics).

  2. anonymous
    • 4 years ago
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    I just plugged it into the simplified form and got 1.55. Is that right?

  3. precal
    • 4 years ago
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    Is this calculus? Particle motion is not that easy.

  4. anonymous
    • 4 years ago
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    no i think it's algebra

  5. precal
    • 4 years ago
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    Ok then let's do it using Algebra only \[\left[ \left( t+2 \right)^2-3t \right]/5\] if t=1.5 then \[\left[ \left( 1.5+2 \right)^2-3*1.5 \right]/5\] \[\left[ \left( 3.5 \right)^2-4.5 \right]/5\] \[\left( 12.25-4.5 \right)/5\] \[\left( 7.75 \right)/5\] 1.55

  6. anonymous
    • 4 years ago
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    grazi, wanna help me with another one, simpler ?

  7. precal
    • 4 years ago
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    Go for it! If I can help you, I will.

  8. anonymous
    • 4 years ago
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    i'm posting it in the chat

  9. precal
    • 4 years ago
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    by the way you answer is correct if you did not have t=1.5

  10. anonymous
    • 4 years ago
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    huh???

  11. precal
    • 4 years ago
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    \[\left( (t+2)^2-3t \right)/5=\left( t^2+t+4 \right)/5\]

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