lilg132
trigonometry help



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lilg132
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dw:1328053926336:dw

lilg132
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i need to work out the length of BC and the phi angle

Mertsj
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Law of Cosines: c^2=5^2+8622(5)(8)cos 115.

Mertsj
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\[(BC)^2=5^2+8^22\times5\times8\cos 115\]

lilg132
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i've been taught just to do
(bc)^2 = ac^2 + ab^2

Mertsj
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then after you find BC use the law of sines.\[\frac{\sin 115}{BC}=\frac{\sin \theta}{5}\]

Mertsj
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this is not a right triangle so the pythagorean theorem does not apply.

lilg132
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ohhh ok

lilg132
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i thought i was doing something wrong :p

lilg132
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let me try and do it now thanks for pointing that out

Mertsj
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yw