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lilg132

  • 2 years ago

trigonometry help

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  1. lilg132
    • 2 years ago
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    |dw:1328053926336:dw|

  2. lilg132
    • 2 years ago
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    i need to work out the length of BC and the phi angle

  3. Mertsj
    • 2 years ago
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    Law of Cosines: c^2=5^2+862-2(5)(8)cos 115.

  4. Mertsj
    • 2 years ago
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    \[(BC)^2=5^2+8^2-2\times5\times8\cos 115\]

  5. lilg132
    • 2 years ago
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    i've been taught just to do (bc)^2 = ac^2 + ab^2

  6. Mertsj
    • 2 years ago
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    then after you find BC use the law of sines.\[\frac{\sin 115}{BC}=\frac{\sin \theta}{5}\]

  7. Mertsj
    • 2 years ago
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    this is not a right triangle so the pythagorean theorem does not apply.

  8. lilg132
    • 2 years ago
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    ohhh ok

  9. lilg132
    • 2 years ago
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    i thought i was doing something wrong :p

  10. lilg132
    • 2 years ago
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    let me try and do it now thanks for pointing that out

  11. Mertsj
    • 2 years ago
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    yw

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