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anonymous
 4 years ago
Consider the 639 N weight held by two cables
shown below. The lefthand cable had ten
sion T2 and makes an angle of 53 with the
ceiling. The righthand cable had tension T1
and makes an angle of 49 with the ceiling.a) What is the tension in the cable labeled
T1 slanted at an angle of 49? b.) And T2 slanted at 53...
anonymous
 4 years ago
Consider the 639 N weight held by two cables shown below. The lefthand cable had ten sion T2 and makes an angle of 53 with the ceiling. The righthand cable had tension T1 and makes an angle of 49 with the ceiling.a) What is the tension in the cable labeled T1 slanted at an angle of 49? b.) And T2 slanted at 53...

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so I have actually worked it out.... once again i need a checker to make sure i did everything right....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok I got Im calling The straight Vector starting at the points where T1 and T2 meet T3. And t3 = m * g = 639N * 9.8 m/s^2= this = 6262.2 N* m /s^2 (im not for sure about the units thats what i need help on) Fx = T1 cos 53 + T2cos 49 = 0 Fy = T1 sin 53 + T2 sin 49  6262.2 = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0.8 T1 + .75T2 = 6262.2 T2 = .6T1/.66

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0look at the link krystal see if that helps u kk?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0t1=4231.22 then plug that in to the other formula T2=3836.31

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hey krystal. Your methodology looks solid. Remember that a Newton has units\[\rm [N] = \left [ kg \cdot m \over s^2 \right]\]Therefore, you don't need to multiply 639N by gravity because in this case Newton is a measure of weight not mass.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so gravity was not needed in this case....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well its always needed :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nope. \[{Newtons \over gravity} = mass\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so dont multiply divide.....ok

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No no no. We want units of Newtons. Sorry for the confusion. Remember that Newton is the unit of force, which is what we are considering here.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0When we say that something weight xxx N, it has already been multiplied by gravity. In other cases, we are given mass and we multiply by gravity to get the weight. Here that has been done for you.
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