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anonymous

  • 4 years ago

The tangent line to the graph of f(x) = x^2 at the point (x, y) has slope = 2x. The equation of the tangent line to the graph of f(x) = x^2 at x = -2 is y =?

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  1. anonymous
    • 4 years ago
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    y=-4x

  2. anonymous
    • 4 years ago
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    slope is -4

  3. anonymous
    • 4 years ago
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    the slope is -4 right ,but y=-4x?

  4. anonymous
    • 4 years ago
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    because f(-2) = -4 right?

  5. anonymous
    • 4 years ago
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    is that correct 14yamaka?

  6. anonymous
    • 4 years ago
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    can you show me how you got that, yamaka?

  7. anonymous
    • 4 years ago
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    sry, just got back XD ok

  8. anonymous
    • 4 years ago
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    I meant slope is four. This is how we get to the answer: FIrst, plug x=-2 in as that is the point where the line and the f(x)=x^2 cross. f(-2)=(x)^2 f(-2)=4 (-2, 4) Now, we also know that slope is 2x. THerefore, slope is -4. So, y=-4x+b 4=-4(-2)+b b=-4 y=-4x-4

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