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anonymous

  • 4 years ago

A block accelerates at 3.7 m/s2 down a plane inclined at an angle 27.0. Find μk between the block and the in- clined plane. The acceleration of gravity is 9.81 m/s2 .

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  1. anonymous
    • 4 years ago
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    Ok once again worked out.... Tcos32=6.5 * 9.8 T=75.12 75.12sin32=6.5 * a a=6.12 Please tell me if this is the right answer....

  2. anonymous
    • 4 years ago
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    ok sorry that is def the wrong question this is the RIGHT question....sorry guys..

  3. anonymous
    • 4 years ago
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    A 6.5 kg object hangs at one end of a rope that is attached to a support on a railroad boxcar. When the car accelerates to the right, the rope makes an angle of 32 with the vertical The acceleration of gravity is 9.8 m/s2 .Find the acceleration of the car. (Hint: ~aobject = ~acar) Answer in units of m/s2

  4. anonymous
    • 4 years ago
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    and actually i dont even have an idea on how to do the question I originally posted.

  5. anonymous
    • 4 years ago
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    Your work looks good. Let me analyze the original question.

  6. anonymous
    • 4 years ago
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    Find the gravitational force acting along the inclined plane and the gravitation force acting normal to the inclined plane. The balance of the force acting along the inclined plane and the friction force will balance to equal the acceleration the object is experiencing. \[m \cdot a = F_{ip} - F_f\]

  7. anonymous
    • 4 years ago
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    ok normal force = m*g cos theta....but how do you find mass???

  8. anonymous
    • 4 years ago
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    Force * Acceleration ahhh duh idiot*

  9. anonymous
    • 4 years ago
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    but then that would be a unit-less number...that cant be right... oh come back my savior

  10. anonymous
    • 4 years ago
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    so i tried this : m * a = m*g*sinA- uk*m*g*cosA a= g*sinA - uk *g*cosA 3.7=9.81 * sin 27 -uk * 9.81 * cos 27 3.7 = 4.45 - 8.74uk 3.7 - 4.45 = -8.74uk .09 = uk ???? yes no maybe??

  11. anonymous
    • 4 years ago
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    Looks good.

  12. anonymous
    • 4 years ago
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    wrong ?????? help.

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