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anonymous

  • 4 years ago

f(x) = x-x^3 a = -0.2 slope =??

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  1. dumbcow
    • 4 years ago
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    could you clarify the question? what does a refer to?

  2. anonymous
    • 4 years ago
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    tangents

  3. anonymous
    • 4 years ago
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    Let f(x) = x-x^3. determine the approximate slope of the line tangent of f at (a, f (a)).

  4. anonymous
    • 4 years ago
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    a = -0.2 slope=?

  5. anonymous
    • 4 years ago
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    I think derivitives

  6. dumbcow
    • 4 years ago
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    ok thank you the slope of f(x) can be determined by taking derivative f'(x) =1 - 3x^2 now plug in x = -0.2 f'(-0.2) = 1 - 3(-.2)^2 = 0.88

  7. anonymous
    • 4 years ago
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    so 0.88 would be the slope?

  8. dumbcow
    • 4 years ago
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    yes f'(x) is same thing as slope at point (x, f(x))

  9. anonymous
    • 4 years ago
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    thank you

  10. dumbcow
    • 4 years ago
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    do you know how to take the derivative of polynomials?

  11. dumbcow
    • 4 years ago
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    d/dx x^n = n*x^(n-1)

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