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anonymous
 4 years ago
Can someone help me write a nonrecursive version if this function in C?
http://db.tt/0NISjQXX
I just started learning C after Scheme and loops are still kind of confusing for me.
anonymous
 4 years ago
Can someone help me write a nonrecursive version if this function in C? http://db.tt/0NISjQXX I just started learning C after Scheme and loops are still kind of confusing for me.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The code doesn't look like c. if it is which version or type is it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you can describe the functionality I can help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok is it computing \[x^{e} \mod m\] And you can write a recursive C version.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0int xsqrm( int x, int m) { return (x * x) % m int powermod2(int x, int e, int m) { if (e == 0) return 1; if (e % 2 == 0) return powermod2(xsqrm(x, m), e/2); return (x * powermod2(xsqrm(x, m), e/2)) % m ; }

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for anyone curious this is the solution I came up with int powmod2(int x, int e, int m) { int y = 1; while (e!= 0) { if (e%2 == 0) { e = e/2; x = (x*x)%m; } else { e = (e1)/2; y = (x*y)%m; x = (x*x)%m; } } return y; } My problem was that I was missing a step in the odd case that I was able to introduce with the y variable. The original I needed to convert this was a recursive version written in scheme. Thanks for your help though!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0e = e/2 is enough in both cases; because integer division truncates. So you can remove the two statements inside the if and else and replace by e /= 2 in the while loop
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