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A pawn broker buys a TV set and a computer for $600. He sells the Computer at a markup of 30% and the TV at a markup of 20%. If he makes a profit of $165 on the sale of two items, what did he pay for the computer?

Mathematics
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if he pays say "x" dollars for the computer then since the total is $600 he must pay 600 - x dollars for the tv. his profit on the computer is \[.3x\] and his profit on the tv is \[.2(600-x)\] and you know this totals 165 so set \[.3x+.2(600-x)=165\] and solve for x
probably easiest to start with \[3x+2(600-x)=1650\] so you don't have the messy demicals
ok perfect thank you I was close when I set my equation up but I think I caught where I was messing up

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