A pawn broker buys a TV set and a computer for $600. He sells the Computer at a markup of 30% and the TV at a markup of 20%. If he makes a profit of $165 on the sale of two items, what did he pay for the computer?
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
if he pays say "x" dollars for the computer then since the total is $600 he must pay 600 - x dollars for the tv. his profit on the computer is
\[.3x\] and his profit on the tv is
\[.2(600-x)\] and you know this totals 165 so set
\[.3x+.2(600-x)=165\] and solve for x
probably easiest to start with
\[3x+2(600-x)=1650\] so you don't have the messy demicals
ok perfect thank you I was close when I set my equation up but I think I caught where I was messing up