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much easier than the last one

Similar to the other one right?

\[\dbinom{3}{2}\times \dbinom{6}{2}\times \dbinom{14}{3}\]

how exactly do i solve that notation?
multiply? Cross multiply?

sorry it has been forever since i had a math class now im in this finite course:)

maybe you have seen it this way instead
\[3C2\]?

yes

3x2x1
-----
2x1
?

how do u get the 6 and 5

the last one is therefore
\[\frac{14\times 13\times 12}{3\times 2}\]

so there are only two then correct?

two what?

are there two cases for this

wow you are a genius
16380

but....im not sure how you got 3x15x364 what do i do with the numbers inside ( ) exactly?

got disconnected