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anonymous

  • 4 years ago

A camper has 3 jackets, 6 sleeping bags, and 14 different packages of food. An outfit consists of 2 jackets, 2 sleeping bags, and 3 packets of food. How many ways can the trip be outfitted?______

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  1. anonymous
    • 4 years ago
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    much easier than the last one

  2. anonymous
    • 4 years ago
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    Similar to the other one right?

  3. anonymous
    • 4 years ago
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    \[\dbinom{3}{2}\times \dbinom{6}{2}\times \dbinom{14}{3}\]

  4. anonymous
    • 4 years ago
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    is it clear how to compute these numbers, because in fact all i really did was restate the question in notation

  5. anonymous
    • 4 years ago
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    how exactly do i solve that notation? multiply? Cross multiply?

  6. anonymous
    • 4 years ago
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    sorry it has been forever since i had a math class now im in this finite course:)

  7. anonymous
    • 4 years ago
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    maybe you have seen it this way instead \[3C2\]?

  8. anonymous
    • 4 years ago
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    yes

  9. anonymous
    • 4 years ago
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    3x2x1 ----- 2x1 ?

  10. anonymous
    • 4 years ago
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    number of ways to choose 2 from a set of 3 is 3 number of ways to choose 2 from a set of 6 is \[\frac{6\times 5}{2}=15\]

  11. anonymous
    • 4 years ago
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    how do u get the 6 and 5

  12. anonymous
    • 4 years ago
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    yes that is one way to think about it. the other way is more basic. if you have three items and wish to select one, you pretty clearly have 3 choices. if you have three items and wish to select 2, you have the same three choice ( like selecting the one to exclude)

  13. anonymous
    • 4 years ago
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    you have 6 sleeping bags and wish to select 2 of them, six choices for first bag, 5 for second and you have to divide by two because order doesn't count

  14. anonymous
    • 4 years ago
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    the last one is therefore \[\frac{14\times 13\times 12}{3\times 2}\]

  15. anonymous
    • 4 years ago
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    so there are only two then correct?

  16. anonymous
    • 4 years ago
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    two what?

  17. anonymous
    • 4 years ago
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    are there two cases for this

  18. anonymous
    • 4 years ago
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    for this problem it is a straightforward multiplication \[\dbinom{3}{2}\times \dbinom{6}{2}\times \dbinom{14}{3}\] \[3\times 15\times 364\]

  19. anonymous
    • 4 years ago
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    wow you are a genius 16380

  20. anonymous
    • 4 years ago
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    but....im not sure how you got 3x15x364 what do i do with the numbers inside ( ) exactly?

  21. anonymous
    • 4 years ago
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    got disconnected

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