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anonymous

  • 4 years ago

You have a committee of 13 members, made up of 8 men and 3 women. In how many ways can 3 tasks be assigned so that both men and women are given assignments?

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  1. anonymous
    • 4 years ago
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    The number of ways in which 3 tasks can be distributed such that only men or only women get the job is. Only men 8C3 Only women : 3C3=1 Total ways: 13C3 Hence the answer would be 13C3-1-8C3

  2. anonymous
    • 4 years ago
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    ill work it out

  3. anonymous
    • 4 years ago
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    that wasnt right

  4. anonymous
    • 4 years ago
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    Hmm okay maybe it was wrong i am not sure....

  5. anonymous
    • 4 years ago
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    would it be a permutation

  6. anonymous
    • 4 years ago
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    No i think it'll be a combination only.

  7. anonymous
    • 4 years ago
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    One task is given to one person only right?

  8. anonymous
    • 4 years ago
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    it just says how many ways can the 3 tasks be assigned so that both women and men are given assignments

  9. dumbcow
    • 4 years ago
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    is that a typo? shouldn't it be 8 men and 5 women

  10. anonymous
    • 4 years ago
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    total 13 members and 3 total tasks

  11. anonymous
    • 4 years ago
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    Is 220 the answer?

  12. anonymous
    • 4 years ago
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    no

  13. dumbcow
    • 4 years ago
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    shankvee had the right idea :) but your numbers don't add up ....8+3 = 11 not 13

  14. anonymous
    • 4 years ago
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    leave u cant read 8+5

  15. dumbcow
    • 4 years ago
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    ?? 13C3 - 8C3 - 5C3 = 286 - 56 - 10 = 220

  16. anonymous
    • 4 years ago
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    sorry thought you were messing with me i am so sorry but 220 is not right

  17. dumbcow
    • 4 years ago
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    maybe it is permutations then.... 13P3 - 8P3 - 5P3 = 1320

  18. anonymous
    • 4 years ago
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    you are a genius

  19. anonymous
    • 4 years ago
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    It was permutations

  20. anonymous
    • 4 years ago
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    I am so sorry for my comment earlier I had some punk on here earlier and thought you were messing with me

  21. anonymous
    • 4 years ago
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    I am very very sorry

  22. dumbcow
    • 4 years ago
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    no prob, just noticed a typo in your question post

  23. anonymous
    • 4 years ago
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    I am so sorry

  24. anonymous
    • 4 years ago
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    I have tried the problem 40 times

  25. dumbcow
    • 4 years ago
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    do you know the formulas for combinations and permutations? most calculators will do them for you as well

  26. anonymous
    • 4 years ago
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    somewhat...i find them confusing and hard to remember also my finite course does not allow calculators during exams so i am trying to do them manually because all of our test questions come from these particular set of problems

  27. anonymous
    • 4 years ago
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    I have a few more permuations and maybe a combo i am going to post that are two part questions....3-5 of these have stumped me, most i can work through

  28. Directrix
    • 4 years ago
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    Should this 13 be 11? Or, are the other two committee members neither female nor male? Just wondering. 13 members, made up of 8 men and 3 women. 8+3 =11. I don't think this is a permutation problem. I could be wrong but what about the 13 committee - those two extra members?

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