You have a committee of 13 members, made up of 8 men and 3 women. In how many ways can 3 tasks be assigned so that both men and women are given assignments?

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- anonymous

The number of ways in which 3 tasks can be distributed such that only men or only women get the job is.
Only men 8C3
Only women : 3C3=1
Total ways: 13C3
Hence the answer would be 13C3-1-8C3

- anonymous

ill work it out

- anonymous

that wasnt right

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## More answers

- anonymous

Hmm okay maybe it was wrong i am not sure....

- anonymous

would it be a permutation

- anonymous

No i think it'll be a combination only.

- anonymous

One task is given to one person only right?

- anonymous

it just says how many ways can the 3 tasks be assigned so that both women and men are given assignments

- dumbcow

is that a typo?
shouldn't it be 8 men and 5 women

- anonymous

total 13 members and 3 total tasks

- anonymous

Is 220 the answer?

- anonymous

no

- dumbcow

shankvee had the right idea :)
but your numbers don't add up ....8+3 = 11 not 13

- anonymous

leave u cant read 8+5

- dumbcow

??
13C3 - 8C3 - 5C3 = 286 - 56 - 10 = 220

- anonymous

sorry thought you were messing with me i am so sorry
but 220 is not right

- dumbcow

maybe it is permutations then....
13P3 - 8P3 - 5P3 = 1320

- anonymous

you are a genius

- anonymous

It was permutations

- anonymous

I am so sorry for my comment earlier I had some punk on here earlier and thought you were messing with me

- anonymous

I am very very sorry

- dumbcow

no prob, just noticed a typo in your question post

- anonymous

I am so sorry

- anonymous

I have tried the problem 40 times

- dumbcow

do you know the formulas for combinations and permutations?
most calculators will do them for you as well

- anonymous

somewhat...i find them confusing and hard to remember
also my finite course does not allow calculators during exams so i am trying to do them manually because all of our test questions come from these particular set of problems

- anonymous

I have a few more permuations and maybe a combo i am going to post that are two part questions....3-5 of these have stumped me, most i can work through

- Directrix

Should this 13 be 11? Or, are the other two committee members neither female nor male? Just wondering.
13 members, made up of 8 men and 3 women. 8+3 =11. I don't think this is a permutation problem. I could be wrong but what about the 13 committee - those two extra members?

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