anonymous
  • anonymous
You have a committee of 13 members, made up of 8 men and 3 women. In how many ways can 3 tasks be assigned so that both men and women are given assignments?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
The number of ways in which 3 tasks can be distributed such that only men or only women get the job is. Only men 8C3 Only women : 3C3=1 Total ways: 13C3 Hence the answer would be 13C3-1-8C3
anonymous
  • anonymous
ill work it out
anonymous
  • anonymous
that wasnt right

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anonymous
  • anonymous
Hmm okay maybe it was wrong i am not sure....
anonymous
  • anonymous
would it be a permutation
anonymous
  • anonymous
No i think it'll be a combination only.
anonymous
  • anonymous
One task is given to one person only right?
anonymous
  • anonymous
it just says how many ways can the 3 tasks be assigned so that both women and men are given assignments
dumbcow
  • dumbcow
is that a typo? shouldn't it be 8 men and 5 women
anonymous
  • anonymous
total 13 members and 3 total tasks
anonymous
  • anonymous
Is 220 the answer?
anonymous
  • anonymous
no
dumbcow
  • dumbcow
shankvee had the right idea :) but your numbers don't add up ....8+3 = 11 not 13
anonymous
  • anonymous
leave u cant read 8+5
dumbcow
  • dumbcow
?? 13C3 - 8C3 - 5C3 = 286 - 56 - 10 = 220
anonymous
  • anonymous
sorry thought you were messing with me i am so sorry but 220 is not right
dumbcow
  • dumbcow
maybe it is permutations then.... 13P3 - 8P3 - 5P3 = 1320
anonymous
  • anonymous
you are a genius
anonymous
  • anonymous
It was permutations
anonymous
  • anonymous
I am so sorry for my comment earlier I had some punk on here earlier and thought you were messing with me
anonymous
  • anonymous
I am very very sorry
dumbcow
  • dumbcow
no prob, just noticed a typo in your question post
anonymous
  • anonymous
I am so sorry
anonymous
  • anonymous
I have tried the problem 40 times
dumbcow
  • dumbcow
do you know the formulas for combinations and permutations? most calculators will do them for you as well
anonymous
  • anonymous
somewhat...i find them confusing and hard to remember also my finite course does not allow calculators during exams so i am trying to do them manually because all of our test questions come from these particular set of problems
anonymous
  • anonymous
I have a few more permuations and maybe a combo i am going to post that are two part questions....3-5 of these have stumped me, most i can work through
Directrix
  • Directrix
Should this 13 be 11? Or, are the other two committee members neither female nor male? Just wondering. 13 members, made up of 8 men and 3 women. 8+3 =11. I don't think this is a permutation problem. I could be wrong but what about the 13 committee - those two extra members?

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