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it has no solution
x cant be grater than -6 and smaller than -9
Jmallis it's easy, if we proceed step by step Let's solve the first equation x+9<0 subtract 9 from both sides x<-9 so x is \((-\infty,-9)\) now from the second equation 2x>-12 or x>-6 so from this equation x is \((-6, \infty)\) now it's given x+9<0 or x>-12 so we have to take union of the two ie x belongs to \((-\infty,-9)\) U \((-6, \infty)\)
Thank-you, you think you can help me with another one ash2326
yeah jmallis, post your question :)
Jmallis , post your question as a new thread, that way you can get more people to respond:)
should be all together
we have -6<=2x-12<=18 add 12 to all sides 6<=2x<=30 divide be 2 the whole inequation 3<=x<=10 As we can see x belongs to [3, 10] do notice that it's closed interval
says to solve compund inequality written in compact form, get x alone in the middle part. Since a compound inequality is really two inequalities in one statement, perform same operations on all 3 parts of inequality
Yeah , that's what I've done, notice I have added 12 to all three simultaneously, and divided by 2 all together.
When I put in [3,10] my homework page had a spaz attack
sorry I made a mistake see this we have -6<=2x-12<=18 add 12 to all sides 6<=2x<=30 divide be 2 the whole inequation 3<=x<=15 As we can see x belongs to [3, 15] do notice that it's closed interval It won't get a attack now:D
It's fine now haha