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anonymous
 4 years ago
Solve compound inequality. Write solution in interval notation. x+9<0 or 2x> 12 (these kill me)
anonymous
 4 years ago
Solve compound inequality. Write solution in interval notation. x+9<0 or 2x> 12 (these kill me)

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y2o2
 4 years ago
Best ResponseYou've already chosen the best response.0x cant be grater than 6 and smaller than 9

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1Jmallis it's easy, if we proceed step by step Let's solve the first equation x+9<0 subtract 9 from both sides x<9 so x is \((\infty,9)\) now from the second equation 2x>12 or x>6 so from this equation x is \((6, \infty)\) now it's given x+9<0 or x>12 so we have to take union of the two ie x belongs to \((\infty,9)\) U \((6, \infty)\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thankyou, you think you can help me with another one ash2326

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1yeah jmallis, post your question :)

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1Jmallis , post your question as a new thread, that way you can get more people to respond:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[6\le2x12\]\[\le18\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0should be all together

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1we have 6<=2x12<=18 add 12 to all sides 6<=2x<=30 divide be 2 the whole inequation 3<=x<=10 As we can see x belongs to [3, 10] do notice that it's closed interval

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0says to solve compund inequality written in compact form, get x alone in the middle part. Since a compound inequality is really two inequalities in one statement, perform same operations on all 3 parts of inequality

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1Yeah , that's what I've done, notice I have added 12 to all three simultaneously, and divided by 2 all together.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0When I put in [3,10] my homework page had a spaz attack

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1sorry I made a mistake see this we have 6<=2x12<=18 add 12 to all sides 6<=2x<=30 divide be 2 the whole inequation 3<=x<=15 As we can see x belongs to [3, 15] do notice that it's closed interval It won't get a attack now:D
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