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Student has 6 ball point pens, 4 ball point pens and 1 felt tip pin. We have to find the no. of ways when he can select no more than 1 ball point pen. No. of ways when he has to select 1 pen and 5 other utensils= 6C1*5C5=30 ways
Did you get it cwhutche?
it wasnt right
still isnt correct
it has beat me
I think I see my error.
do ya i still cant figure this out
Zero or one ball point pens will be chosen. There are C(4,0) times C(7,6) = 7 ways to choose 6 writing instruments that are not ball points. [Choose none of the ball points and 6 of the other 7.] There are C(4,1) times C(7,5) ways to choose 6 writing instruments, exactly one of which is a ball point pen .[Choose one of the ball points and 5 of the others.] There are, then, (4) (21) = 84 ways to choose 1 ball point and 5 others. That gives 7 + 84 = 91 ways to choose 6 writing instruments, at most one of which is a ball pen. answer: 91
What about now, CW?
That is it man.... awesome I appreciate it
yw. Sorry for my arithmetic errors early on.
no problem i made a million of them and had no clue i appreciate your time on this problem very much